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Monday, 4 June 2018

NECO 2018 Physics Practical Answer – June/July Expo

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NECO Physics Practical Solution Questions and Answer – JUNE/JULY 2018 Expo Runz.


    CLICK HERE FOR NO.2 IMAGE
    2)
    Tabulate
    Cos @ – |75|65|55|45|35|
    MO(cm)- |1.1|2.0|2.5|3.4|3.9|
    NO(cm)- |6.2|6.4|6.6|6.8|7.2|
    H=MO/NO- |0.177|0.313|0.379|0.500|0.542|
    Cos @ – |0.2588|0.4226|0.5736|0.7071|0.8192|
    2aix)
    CLICK HERE FOR NO.2 GRAPH
    From the graph
    Slope
    S =Δcostita/^ΔH
    =0.75-0.45/0.5-0.3
    =0.3/0.2
    =1.5
    2bi)
    Snell’s law is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.
    i;e sini/sini=n
    were n is known as refractive index
    2bii)
    given refractive index of glass =1.5
    i;e a N g =1.5 (from air to glass)
    sin C/sin90=gNa
    sinC/sin90=1/aNg
    sinC/1=1/1.5
    since=0.6667
    C=sin^-1(0.6667)
    critical angle for glass,C =42degree
    2biii)
    i)I Ensured that the pins were vertical
    ii)I Avoided parallax error when reading protractor.


    CLICK HERE FOR NO.3 IMAGE
    3)
    ii) Vo=2.00V
    3v)
    Tabulate
    S/N – |1|2|3|4|5|
    R(n) – |2|3|4|5|6|
    V(v) – 2.10|2.30|2.40|2.50|2.60|
    R^-1(n^-1)- |0.500|0.333|0.250|0.200|0.167|
    V^-1(V^-1)- |0.476|0.435|0.417|0.400|0.385|
    3aix)
    CLICK HERE FOR NO.3 GRAPH
    3vii)
    Slope
    =Δv^-1/ΔR-1
    =0.5 – 0.355/0.6 – 0
    =0.145/0.6
    S= 0.242
    Intercept
    C = 0.355v^-1
    3aviii)
    K= S/C
    K= 0.242/0.355
    K= 0.68
    3ix)
    i)I ensured that the terminals were firmly tight to prevent partial contact
    ii)I avoided parallax error when taking reading from the voltmeter.


    3bi)
    i)temperature of wire
    ii)cross-sectional area of wire
    iii)length of wire
    iv)nature of wire
    3bii)
    effective E.M.F =2V (parallel connection)
    effective internal resistance =rxr/r+r=r/2 n
    current I =0.8A
    external Resistance R =2n
    using
    E=I(R+r)
    2=0.8(2+r/2)
    2.5=(2+r/2)
    2.5-2=r/2
    0.5=r/2
    r=0.5×2=1n


    COMPLETED – GOOD LUCK
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