## NABTEB GCE Mathematics Obj And Essay/Theory Solution Questions and Answer – NOV/DEC 2017 Expo Runz.

**Maths OBJ:**

1-10=BDBADCDBBB

11-20=BACDCCCACD

21-30=BACCDBABAC

31-40=CCCADBCBCB

41-50=ACCDADACBD

1-10=BDBADCDBBB

11-20=BACDCCCACD

21-30=BACCDBABAC

31-40=CCCADBCBCB

41-50=ACCDADACBD

NOTE:

* means MULTIPLICATION/TIMES

/ means DIVISION

^ means RAISE TO POWER

NOTE:

* means MULTIPLICATION/TIMES

/ means DIVISION

^ means RAISE TO POWER

SECTION A: Answer All Questions(1 to 5)

1a)

123.24base8 - ()base10

= 1*8^2 + 2*8^1 + 3*8^0 + 2*8^-1 + 4*8^-2

= 64 + 16 + 3 + 2/8 + 4/64

= 83 + 1/4 + 1/16

= 83 + 4+1/16

= 83 + 5/16

= 83^5/16base10

1b)

8^1/3 * 5^2/3 * 10^-2/3

2^3/3 * 5^2/3 * (2*5)^2/3

2^1 * 5^2/3 * 2^-2/3 * 5^-2/3

2^1 * 2^-2/3 * 5^2/3 * 5^-2/3

2^1-2/3 * 5^2/3-2/3

2^3-2/3 * 5^0

2^1/3 * 1

= 2^1/3

SECTION A: Answer All Questions(1 to 5)

1a)

123.24base8 - ()base10

= 1*8^2 + 2*8^1 + 3*8^0 + 2*8^-1 + 4*8^-2

= 64 + 16 + 3 + 2/8 + 4/64

= 83 + 1/4 + 1/16

= 83 + 4+1/16

= 83 + 5/16

= 83^5/16base10

1b)

8^1/3 * 5^2/3 * 10^-2/3

2^3/3 * 5^2/3 * (2*5)^2/3

2^1 * 5^2/3 * 2^-2/3 * 5^-2/3

2^1 * 2^-2/3 * 5^2/3 * 5^-2/3

2^1-2/3 * 5^2/3-2/3

2^3-2/3 * 5^0

2^1/3 * 1

= 2^1/3

2a)

y=1+2x/x-2

:- 2x+y = ?

= 2x/1 = 1+2x/x-2

= 2x/1+1+2x/x-2

= 2x(x-2)+(1+2x)/x-2

= 2x^2-4x+1+2x/x-2

= 2x^2-2x+1/x-2

2b)

if x+1/2 = x-3+5/x

:- x+2/2 - 5/x = x-3

x(x+1)-5(2)/2x = x-3

x^2+x-10 = 2x(x-3)

x^2+x-10 = 2x^2-6x

x^2-2x^2+x+6x-10 = 0

-x^2+7x-10 = 0

x^2-7x+10 = 0

x(x-5)-2(x-5) = 0

(x-2)(x-5) = 0

x=2 or x=5

2a)

y=1+2x/x-2

:- 2x+y = ?

= 2x/1 = 1+2x/x-2

= 2x/1+1+2x/x-2

= 2x(x-2)+(1+2x)/x-2

= 2x^2-4x+1+2x/x-2

= 2x^2-2x+1/x-2

2b)

if x+1/2 = x-3+5/x

:- x+2/2 - 5/x = x-3

x(x+1)-5(2)/2x = x-3

x^2+x-10 = 2x(x-3)

x^2+x-10 = 2x^2-6x

x^2-2x^2+x+6x-10 = 0

-x^2+7x-10 = 0

x^2-7x+10 = 0

x(x-5)-2(x-5) = 0

(x-2)(x-5) = 0

x=2 or x=5

3a)

victor investment = N6m

nasiru investment = N3.6m

total investment = N9.6m

proft = turnover-investment

= Nxm-N9.6m

nasiru total take home

= 30%+3.6/9.6*70% = 56.25%

= 56.25/100*[Nxm-N9.6m]

3b)

Victor's collection rate

=N6m/N9.6m*70%

=43.75%

3a)

victor investment = N6m

nasiru investment = N3.6m

total investment = N9.6m

proft = turnover-investment

= Nxm-N9.6m

nasiru total take home

= 30%+3.6/9.6*70% = 56.25%

= 56.25/100*[Nxm-N9.6m]

3b)

Victor's collection rate

=N6m/N9.6m*70%

=43.75%

4a)

S = n/2{2a+(n-1)d}

2S = 2an+(n^2-n)d

2S - (n^2-n)d = 2an

a = 2S-(n^2-n)d/2n

4b)

a=?, S= -890, d= -5, n=20

but a=2S-(n^2-n)d/2n

a=2(-890)-(20^2-20)-5/2(20)

a=-1780-(400-20)-5/40

a=-1780+380(S)/40

a=-1780+1900/40

a=120/40 = 3

a=3

4a)

S = n/2{2a+(n-1)d}

2S = 2an+(n^2-n)d

2S - (n^2-n)d = 2an

a = 2S-(n^2-n)d/2n

4b)

a=?, S= -890, d= -5, n=20

but a=2S-(n^2-n)d/2n

a=2(-890)-(20^2-20)-5/2(20)

a=-1780-(400-20)-5/40

a=-1780+380(S)/40

a=-1780+1900/40

a=120/40 = 3

a=3

5a)

X={1,3,5,7,9,11}

Y={2,3,5,7,11,15}

Z={3,6,9,12,15}

U={1,2,3,...15}

•CLICK HERE FOR THE DIAGRAM

5b)

A≡X

b≡Y

C≡X

(i)AnBnC={3}

A^1={4,6,8,10,12,13,14,15}

B^1={1,4,6,8,10,12,13,14}

:- n(A^1nB^1nC) = {6,12}

5a)

X={1,3,5,7,9,11}

Y={2,3,5,7,11,15}

Z={3,6,9,12,15}

U={1,2,3,...15}

•CLICK HERE FOR THE DIAGRAM

5b)

A≡X

b≡Y

C≡X

(i)AnBnC={3}

A^1={4,6,8,10,12,13,14,15}

B^1={1,4,6,8,10,12,13,14}

:- n(A^1nB^1nC) = {6,12}

SECTION B: Answer according to instruction

8a)

2x-1/x^2+2x-15

i)for zero, numerator = 0

2x-1=0

2x=1

x=1/2

ii)for undefined fraction, denominator = 0

x^2+2x-15=0

x^2+5x-3x-15=0

x(x+5)-3(x+5)

(x-3)(x+5)=0

x=3 or -5

8bi)

internal diameter = 12cm

internal radius = 12/2 = 6cm

thickness = 2cm

extrenal diameter = 12+4=16cm

external radius = 8cm

i)volume = 2/3πr^3

= 2/3*22/7{R^3 - r^2}

= 44/21{8^3-6^3}

= 44/21{512-216}

= 44/21{296} = 13024/21

= 620.19cm^3

8bii)

Area of top = πr^2

= 22/7{8^2 - 6^2}

= 22/7{64 - 36}

= 22/7{28}

= 22*4

= 88cm

SECTION B: Answer according to instruction

8a)

2x-1/x^2+2x-15

i)for zero, numerator = 0

2x-1=0

2x=1

x=1/2

ii)for undefined fraction, denominator = 0

x^2+2x-15=0

x^2+5x-3x-15=0

x(x+5)-3(x+5)

(x-3)(x+5)=0

x=3 or -5

8bi)

internal diameter = 12cm

internal radius = 12/2 = 6cm

thickness = 2cm

extrenal diameter = 12+4=16cm

external radius = 8cm

i)volume = 2/3πr^3

= 2/3*22/7{R^3 - r^2}

= 44/21{8^3-6^3}

= 44/21{512-216}

= 44/21{296} = 13024/21

= 620.19cm^3

8bii)

Area of top = πr^2

= 22/7{8^2 - 6^2}

= 22/7{64 - 36}

= 22/7{28}

= 22*4

= 88cm

10)

•CLICK HERE FOR THE TABLE

x̅ = Ʃfx/Ʃf = 3035/50 = 60.7

a)mean deviation = Ʃf|d|/Ʃf

= 748.8/50

= 14.98

b)standard deviation = rootƩfd^2/Ʃf

= root16224/50

= root324.48

= 18.01

10)

•CLICK HERE FOR THE TABLE

x̅ = Ʃfx/Ʃf = 3035/50 = 60.7

a)mean deviation = Ʃf|d|/Ʃf

= 748.8/50

= 14.98

b)standard deviation = rootƩfd^2/Ʃf

= root16224/50

= root324.48

= 18.01

11ai)

education = 350

medicine = 150

engineering = 200

law = 100

arts = 100

total = 900

angular sector

i)

education = 350/900*360

= 140°

ii)

medicine = 150/900*360

= 60°

iii)

engineering = 200/900*360

= 80°

iv)

law = 100/900*360

= 40°

v)

arts = 100/900*360

= 40°

11aii)

% of students admitted into faculty of education = 350/900*100%

= 350/9

= 38.9%

11bi)

P(B)=3/12 = 1/4

P(W)=4/12 = 1/3

P(R)=5/12

P(one of each ball)=1/4*4/11*5/10* + 1/3*3/11*4/10* + 5/12*3/11*4/10

= 1/22+2/55+1/22

= 5+4+5/110

= 14/110 = 7/55

11bii)

P(at least two red)

= 5/12*P(RRR1)+P(RR1R)+P(RRR)

= 5/12*4/11*7/10 + 5/12*7/11*3/10 + = 5/12*4/11*3/10

= 7/66 + 7/88 + 1/11

= 28+21+24/264

= 73/264

11ai)

education = 350

medicine = 150

engineering = 200

law = 100

arts = 100

total = 900

angular sector

i)

education = 350/900*360

= 140°

ii)

medicine = 150/900*360

= 60°

iii)

engineering = 200/900*360

= 80°

iv)

law = 100/900*360

= 40°

v)

arts = 100/900*360

= 40°

11aii)

% of students admitted into faculty of education = 350/900*100%

= 350/9

= 38.9%

11bi)

P(B)=3/12 = 1/4

P(W)=4/12 = 1/3

P(R)=5/12

P(one of each ball)=1/4*4/11*5/10* + 1/3*3/11*4/10* + 5/12*3/11*4/10

= 1/22+2/55+1/22

= 5+4+5/110

= 14/110 = 7/55

11bii)

P(at least two red)

= 5/12*P(RRR1)+P(RR1R)+P(RRR)

= 5/12*4/11*7/10 + 5/12*7/11*3/10 + = 5/12*4/11*3/10

= 7/66 + 7/88 + 1/11

= 28+21+24/264

= 73/264

13a)

gross income = 2,500,000

personal allowance = 150,000

children(3) = 60,000

insurance(2) 2% of gross = 50,000

contribution(2) 8% of gross = 200,000

total = 460,000

taxable income = 204000

a)

Monthly gross pay

= 2,500,000/12

= N208333.33

b)Tax pay

5% 0f 1st N30,000

= 5/100*30,000

= N15,000

10% of next N30,000

= 10/100*30000

= N3,000

15% of next N50,000

= 15/100*50,000

= 7,500

20% of next 50,000

20/100*50,000

N10,000

25% on remaining = 25/100*(2040000-160,000)

= 25/100*1880000

= N470,000

therefore:

tax pay = 1500+300+7500+470000+110,000

= 492,000

monyhly tax = 492,000/12

= N41,000

c)Next pay = 2,500,000 - 49,200

= N2008000

monthly next pay = 2008000/12

= N167333.33

13a)

gross income = 2,500,000

personal allowance = 150,000

children(3) = 60,000

insurance(2) 2% of gross = 50,000

contribution(2) 8% of gross = 200,000

total = 460,000

taxable income = 204000

a)

Monthly gross pay

= 2,500,000/12

= N208333.33

b)Tax pay

5% 0f 1st N30,000

= 5/100*30,000

= N15,000

10% of next N30,000

= 10/100*30000

= N3,000

15% of next N50,000

= 15/100*50,000

= 7,500

20% of next 50,000

20/100*50,000

N10,000

25% on remaining = 25/100*(2040000-160,000)

= 25/100*1880000

= N470,000

therefore:

tax pay = 1500+300+7500+470000+110,000

= 492,000

monyhly tax = 492,000/12

= N41,000

c)Next pay = 2,500,000 - 49,200

= N2008000

monthly next pay = 2008000/12

= N167333.33

15a)

R=4%

T=5years

A=142,000

I=?

P=?

But I=PRT/100 = P*4*5/100 = 20P/100

I=P/5

but A=P+I

:- 142,000 = P+P/5

142,000 = 5P+P/5

142,000*5 = 6P

P = 142,000*5/6

P = N118333.33

15b)

cash price = N82,000

deposit = N40,000

instalment = N2,500 for 24months

:- Total instalment = 2,500*24

=N60,000

Total amount paid on hire purchase = 40,000+60,000

= N100,000

difference between cash price and hire purchase

=100,000 - 82,000

N18,000

15c)

~for the first year~

Depreciates = 3.5/100*55,000 = N1925

actual cost in 1st quarter = N53075

in 2nd quarter

Depreciate 3.5/100*53075 = N1857.63

actual cost in 2nd quarter = N51217.37

3rd quater

Dep = 3.5/100*51217.37 = N1792.61

actual cost in 3rd quarter = N49424.76

4th quarter

Dep = 3.5/100*49424.76 = N1729.87

actual cost in 4th quarter = 47694.76.89

:- at the end of the first year, the bike cost N47694.89

~for the second year~

1st quarter

dep = 3.5/100*47694.89 = N 1669.32

actual cost = N46025.57

2nd quarter

dep = 3.5/100*46025.57 = N1610.89

actual cost = N44414.68

3rd quarter

dep = 3.5/100*44414.68 = N1554.51

actual value = N42860.06

4th quarter

dep = 3.5/100*42860.06 = 1500.10

actual cost = N41359.96

at the end of 2years cost = N41359.96

15a)

R=4%

T=5years

A=142,000

I=?

P=?

But I=PRT/100 = P*4*5/100 = 20P/100

I=P/5

but A=P+I

:- 142,000 = P+P/5

142,000 = 5P+P/5

142,000*5 = 6P

P = 142,000*5/6

P = N118333.33

15b)

cash price = N82,000

deposit = N40,000

instalment = N2,500 for 24months

:- Total instalment = 2,500*24

=N60,000

Total amount paid on hire purchase = 40,000+60,000

= N100,000

difference between cash price and hire purchase

=100,000 - 82,000

N18,000

15c)

~for the first year~

Depreciates = 3.5/100*55,000 = N1925

actual cost in 1st quarter = N53075

in 2nd quarter

Depreciate 3.5/100*53075 = N1857.63

actual cost in 2nd quarter = N51217.37

3rd quater

Dep = 3.5/100*51217.37 = N1792.61

actual cost in 3rd quarter = N49424.76

4th quarter

Dep = 3.5/100*49424.76 = N1729.87

actual cost in 4th quarter = 47694.76.89

:- at the end of the first year, the bike cost N47694.89

~for the second year~

1st quarter

dep = 3.5/100*47694.89 = N 1669.32

actual cost = N46025.57

2nd quarter

dep = 3.5/100*46025.57 = N1610.89

actual cost = N44414.68

3rd quarter

dep = 3.5/100*44414.68 = N1554.51

actual value = N42860.06

4th quarter

dep = 3.5/100*42860.06 = 1500.10

actual cost = N41359.96

at the end of 2years cost = N41359.96

GOOD LUCK

=========================

*042tvseries.com send all exam expo answer earlier than others*============================

**GOODLUCK!!!**

*NABTEB GCE ssce 2017 Mathematics expo answers, Ssce 2017 Mathematics objective and essay Expo answers now available, nov/dec Mathematics theory Answers for 2017, Mathematics obj and theory Questions NABTEB GCE Ssce Expo Answers Here, Free wassce Mathematics objective, essay & theory correct Expo 2017 answers Runz NABTEB GCE Mathematics, NABTEB GCE Ssce 2017 Free Mathematics essay, obj and theory Questions and Answers Expo for NABTEB GCE Mathematics, Wassce 2017 Free Mathematics Paper 1 and Paper 2 objective and essay Questions and Answers Expo Now Posted, Free Mathematics objective ans for internal ssce, see NABTEB GCE ssce expo Mathematics obj and theory, essay questions for free, loadedexpo correct wassce Mathematics*

*ans, sure NABTEB GCE ssce Mathematics objective answers runz runs expo free real and correct NABTEB GCE ssce 2017 nov/dec Mathematics free expo runz runs ans answers online for free see free answers online, 2017 Verified NABTEB GCE Free Ssce Mathematics Obj and theory Answers have been posted REAL NABTEB GCE SSCE Mathematics QUESTIONS & ANSWERS Direct To Phone Number AS Text message, RE: 2017 WASSCE Mathematics (Expo) NABTEB GCE 2017 certified runs Mathematics questions and answers NABTEB GCE SSCE November/December 2017 Mathematics THEORY / ESSAY / OBJ QUESTION AND EXPO I need NABTEB GCE ssce free expo site, how can I get NABTEB GCE Mathematics answer for free, NABTEB GCE 2017 Mathematics essay, Objective And Theory Question and Answer Now Posted, Real 2017/2018 nov/dec wassce NABTEB GCE Mathematics objective, essay and theory 100% correct expo questions and answers runz chokes runs, verified 2017 NABTEB GCE Mathematics theory, essay and obj NABTEB GCE Mathematics expo website, NABTEB GCE ssce Mathematics live cheats, sure November/December NABTEB GCE SSCE 2017 Mathematics original objective, theory and essay questions and answer now available here, 100% NABTEB GCE ssce Mathematics expo, 2017 wassce Mathematics obj, essay and theory runz now posted, correct NABTEB GCE ssce Mathematics objective, essay (theory) answer now ready, free 2017 wassce Mathematics obj, theory and essay best expo site NABTEB GCE ssce Mathematics questions and answers, password for certified NABTEB GCE ssce Mathematics essay theory obj expo, how to get/ where to get wassce Mathematics theory, essay and objective expo answer direct to my phone as text message, trusted NABTEB GCE ssce Mathematics questions and answer, i need NABTEB GCE Ssce nov/dec Mathematics essay theory objective obj Expo 2017 answers on whatsapp, gidifans Mathematics answer, solutionclass Mathematics answer, 042tvseries Mathematics answer, codedexam NABTEB GCE Mathematics answer, wapbaze Mathematics answer, wapextra Mathematics expo, Martinlibrary Mathematics expo, examgists NABTEB GCE Mathematics expo, NABTEB GCE Mathematics objectives answer, naija NABTEB GCE Mathematics expo free answer*

**ARE YOU WRITING JAMB 2019/2020 CLICK TO JOIN WHATSAPP GROUP**

**ARE YOU WRITING WAEC 2019/2020 CLICK TO JOIN WHATSAPP GROUP**

previous article

Newer Post

## No comments

## Post a Comment